8^2x-3=(1/16)^x-2

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Solution for 8^2x-3=(1/16)^x-2 equation: 



8^2x-3=(1/16)^x-2

We move all terms to the left:

8^2x-3-((1/16)^x-2)=0



Domain of the equation: 16)^x-2)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

8^2x-((+1/16)^x-2)-3=0

We multiply all the terms by the denominator


8^2x*16)^x-2)-((-3*16)^x-2)+1=0

We add all the numbers together, and all the variables

8^2x*16)^x-2)-((-48)^x-2)+1=0

Wy multiply elements

128x^3-48)^x-2)+1=0

We do not support expression: x^3

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